помогите пожалуйста это срочно
[tex] \frac{1}{x -2}+\frac{x}{x+2}= \frac{4}{x^2-4}- \frac{2x}{x+2} [/tex]
[tex] \frac{1}{x -2}+\frac{x}{x+2}= \frac{4}{x^2-4}- \frac{2x}{x+2} [/tex]
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х+2+х-2=4-2х(х-2)
2х=4-4х²+4х
4х²-4х-4+2х=0
4х²-2х-4=0
2х²-х-2=0
D=1+16=17
х=(1+√17):4
х=(1-√17):4