Помогите решить уравнения, дам 10 б
1) -2x-[tex]1\frac{2}{5} [/tex]=6x-3
2)[tex] \frac{5}{x-3}=- \frac{6}{13} [/tex]
3)[tex] \frac{3-2(1-x)}{4} = \frac{5}{2} [/tex]
1) -2x-[tex]1\frac{2}{5} [/tex]=6x-3
2)[tex] \frac{5}{x-3}=- \frac{6}{13} [/tex]
3)[tex] \frac{3-2(1-x)}{4} = \frac{5}{2} [/tex]
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