Сократите дробь:
a)[tex] \frac{ t^{2}-36 }{6+t} [/tex]
б)[tex] \frac{5k-2l}{ 25k^{2}-4l^{2}} [/tex]
a)[tex] \frac{ t^{2}-36 }{6+t} [/tex]
б)[tex] \frac{5k-2l}{ 25k^{2}-4l^{2}} [/tex]
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Answers & Comments
б) 5к-2i / 25k²-4i² = 5k-2i / (5k-2i) (5k+2i) = 1/ (5k+2i)