Найдите сумму целых решений неравенства
[tex]4^{x} - 20* 2^{x} +51\ \textless \ 0[/tex]
[tex]4^{x} - 20* 2^{x} +51\ \textless \ 0[/tex]
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4^x-20*2^x+51<02^x=v
v²-20v+51=0 D=196
v₁=17 v₂=3
-∞_____+______3______-____17______+____+∞ ⇒
v=(2^x)∈(3;17) ⇒
Целые решения: х₁=2 х₂=3 х₃=4 ⇒
Σ=2+3+4=9.