Помогите решить пожалуйста!!! интеграл [tex]1/(x\sqrt(2-3ln^2x))[/tex]. Created by nastysh20011. algebra-ru

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nastysh20011 @nastysh20011

October 2021 1 20 Report

Помогите решить пожалуйста!!! интеграл [tex]1/(x\sqrt(2-3ln^2x))[/tex]

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NNNLLL54

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$\int \frac{dx}{x\cdot \sqrt{2-3ln^2x}}=\int \frac{1}{\sqrt{2-3ln^2x}}\cdot \frac{dx}{x}=[\; t=lnx\; ,\; dt=\frac{dx}{x}\; ]=\int \frac{dt}{\sqrt{2-3t^2}}=\\\\=\frac{1}{\sqrt3}\cdot arcsin\frac{\sqrt3t}{\sqrt2}+C=\frac{1}{\sqrt3}\cdot arcsin\frac{\sqrt3\, lnx}{\sqrt2}+C\; ;\\\\\\\star \; \int \frac{dx}{\sqrt{a^2-x^2}}=arcsin\frac{x}{a}+C\; \; \star$

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nastysh20011 August 2022 | 0 Ответы

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1,3810^(-23) 10 =...

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Verified answer

pomogitee pozhalujsta napishite pozhalujsta 7 10 predlozhenij na anglijskom yazyke

parallelnoe soedinenie s raznym soprotivleniem r12 r24 obshaya sila toka 3

1,38*10^(-23) * 10 =...

tex]...

pozhalujsta kakoj obem co2 obrazuetsya pri sgoranii 600 gramm pentana esli ma

tex]...

tex]...

tex]...

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1,3810^(-23) 10 =...