Упростите выражение:
[tex](\frac{2a+1}{a^2-9})^-1 *( \frac{4a}{2a-1}- \frac{12a+1}{2a^2+5a-3}) [/tex]
[tex](\frac{2a+1}{a^2-9})^-1 *( \frac{4a}{2a-1}- \frac{12a+1}{2a^2+5a-3}) [/tex]
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1)4a/(2a-1)-(12a+1)/[(2a-1)(a+3)]=(4a²+12a-12a-1)/[(2a-1)(a+3)]==(4a²-1)/[(2a-1)(a+3)]=(2a-1)(2a+1)/[(2a-1)(a+3)]=(2a+1)/(a+3)
2)(a-3)(a+3)/(2a+1)*(2a+1)/(a+3)=(a-3)