а) (√3-√5)² = (3-2*√3*√5+5)= 3-2√15+5=8-2√15=2(4-√15)
б) (3√5-2)²=(9*5-12√5+4)=45-12√5+4=49-12√5
в) (2√3+3√2)²=(4*3+12√3*√2+9*2)=12+12√6+18=30+12√6=3(10+4√6)
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а) (√3-√5)² = (3-2*√3*√5+5)= 3-2√15+5=8-2√15=2(4-√15)
б) (3√5-2)²=(9*5-12√5+4)=45-12√5+4=49-12√5
в) (2√3+3√2)²=(4*3+12√3*√2+9*2)=12+12√6+18=30+12√6=3(10+4√6)