Найдите область определения. [tex]y=\sqrt{x^2-3x-10}-\frac{5}{x^2-9}[/tex]. Created by knovytska. algebra-ru

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Найдите область определения.

[tex]y=\sqrt{x^2-3x-10}-\frac{5}{x^2-9}[/tex]

Rechnung

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$\begin{cases} x^2-3x-10\geq0\\x^2-9\neq0 \end{cases}\\\\\begin{cases} (x+2)(x-5)\geq0\\(x-3)(x+3)\neq0 \end{cases}\\\\\begin{cases} (x+2)(x-5)\geq0\\x\neq+-3 \end{cases}$

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_______-3 ________ -2 ___________ 3 ______________ 5 ________________

$x\in(-\infty;-3)\cup(-3;-2]\cup[5;+\infty)$

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