Найдите количество целых решений неравенства: [tex]3 * 4^{x} - 5* 6^{x} + 2 * 9^{x} \leq 0[/tex]. Created by pomogite121415. algebra-ru

tex]...

December 2021 1 19 Report

Найдите количество целых решений неравенства:
[tex]3 * 4^{x} - 5* 6^{x} + 2 * 9^{x} \leq 0[/tex]

Answers & Comments

Alexandr130398 $3*4^x-5*6^x+2*9^x \leq 0 \\ \\ 3*4^x-5*6^x+2*9^x= 0 \ | :9^x, \ 9^x \neq 0 \\ \\ 3* (\frac{4}{9} )^x-5* (\frac{6}{9} )^x+2=0 \\ \\ 3* (\frac{2}{3} )^{2x}-5* (\frac{2}{3} )^x+2=0 \\ \\ (\frac{2}{3} )^x=t, \ t\ \textgreater \ 0 \\ \\ 3t^2-5t+2=0 \\ \\ D=25-24=1 \\ \\ t_1= \frac{5-1}{6}= \frac{2}{3} \\ \\ t_2= \frac{5+1}{6} =1 \\ \\ 1) (\frac{2}{3} )^x=\frac{2}{3} \\ \\ x=1 \\ \\ 2) \ (\frac{2}{3})^x=1 \\ \\ (\frac{2}{3})^x=(\frac{2}{3})^0 \\ \\ x=0$

$3*4^x-5*6^x+2*9^x \leq 0 \\ \\ +++++[0]----[1]+++++\ \textgreater \ x \\ \\ x \in [0;1]$

Целые решения: 0; 1
количество целых решений: 2

Ответ: 2

1 votes Thanks 1

pomogite121415 Огромное спасибо!

Answers & Comments

napishite pozhalujsta rasskaz chtob v nem bylo o morali dolge dobre zle i sov

ogromnaya prosba pomoch s resheniem lodu yxydxxdy

najdite oshibku rot glotka traheya pishevod zheludok pochki tonkaya kishka tolstaya kish

najdite pervyj chlen vozrastayushej geometricheskoj progressii esli a1a2a38 a1

v geometricheskoj progressii b1b95 i b12 b9217 najdite b4b6

pomogite pozhalujsta dayu 99 ballov peredelat predlozheniya v passive voice 1

pomogite pozhalujsta dayu 99 ballov peredelat predlozheniya v passive voice1

proshu ochen nuzhna pomosh myshkuyushaya lisica medlenno idet protiv vetra vot ona

pozhalujsta pomogite gazoobraznoe veshestvo obemom 4 dm3 pri polnom szhiganii

ochen nuzhna pomosh 1 kakie predlozheniya sootvetstvuyut privedyonnoj sheme u

рекомендуемые вопросы

Helpful Links

Helpful Social