Home
О нас
Products
Services
Регистрация
Войти
Поиск
aliana123
@aliana123
July 2022
1
8
Report
помогите))) найти производные первого порядка длинных функций, используя правила вычисления производных:
1) [tex]y= 8x-\frac{5}{ x^{4} } + \frac{1}{x} - \sqrt[5]{ x^{4} } [/tex]
2) [tex][tex]y=2 x^{ctg ^{2}x } (5 x^{3} + \sqrt[3]{x} ) [/tex]
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
karasikov
1)
f(x) = y = 8x - 5x^(-4) + x^(-1) - x^(4/5);
f'(x) = 8 + 20x^(-5) - x^(-2) - 4/5x^(-1/5);
2)
вначале найдем производную
x^(ctgx^2):
g(x) =
x^(ctgx^2);
ln(g(x))' = 1/g(x) * g'(x);
g'(x) = g(x)*(lng(x))';
(lng(x))' = (ln
x^(ctgx^2))' = (ctgx^2lnx)' = 2*ctgx*(-1/sin^2x)*lnx + ctg^2x/x;
g'(x) =
x^(ctg^2x) * (2 * ctgx * (
-1/sin^2x) * lnx + (ctg^2x)/x);
f(x) = y = 2x^(ctgx^2)*(5x^3 + x^(1/3));
f'(x) = 2 * g'(x) * (5x^3 + x^(1/3)) + 2 * g(x) * (15x^2 + 1/3x^(-2/3));
f'(x) = 2 * x^(ctg^2x) * (2 * ctgx * (-1/sin^2x) * lnx + (ctg^2x)/x) * (5x^3 + x^(1/3)) + 2 *
x^(ctg^2x) * (15x^2 + (1/3)x^(-2/3)).
2 votes
Thanks 1
aliana123
спасибо))
More Questions From This User
See All
aliana123
August 2022 | 0 Ответы
raspredelite privedyonnye nizhe slova na gruppypodpishite nazvanie grupp1avstral1b8654fde51a0cd665a0cf325377bf58 11012
Answer
aliana123
August 2022 | 0 Ответы
pomogite pozhalujsta perepishite i perevedite predlozheniya opredelite kakoj cha
Answer
aliana123
August 2022 | 0 Ответы
tekst rassuzhdeniesochinenie na temu shenokc5b37ac1f34f4e7f958f8be2fd06c8c2 80424
Answer
aliana123
August 2022 | 0 Ответы
pomogite reshit x21x
Answer
aliana123
August 2022 | 0 Ответы
pridumat drugoj konec ballady kubok pozhalujstoo
Answer
aliana123
July 2022 | 0 Ответы
srochno pozh tazadanie 1 prochitajte stihotvorenie i bunina pervyj sneg per
Answer
aliana123
July 2022 | 0 Ответы
pomogite pozh tauchyonyj innokentij ivanov poluchil priglashenie vystupat s dokla
Answer
aliana123
July 2022 | 0 Ответы
1 im a nurse and do you do a how b what c which d who 2 can i have
Answer
aliana123
July 2022 | 0 Ответы
39. I tried to call you but your line was ___. a) taken b) occupied c) engaged d...
Answer
aliana123
July 2022 | 0 Ответы
39. I tried to call you but your line was ___. a) taken b) occupied c) engaged d...
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "tex]..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
f(x) = y = 8x - 5x^(-4) + x^(-1) - x^(4/5);
f'(x) = 8 + 20x^(-5) - x^(-2) - 4/5x^(-1/5);
2)
вначале найдем производную x^(ctgx^2):
g(x) = x^(ctgx^2);
ln(g(x))' = 1/g(x) * g'(x);
g'(x) = g(x)*(lng(x))';
(lng(x))' = (lnx^(ctgx^2))' = (ctgx^2lnx)' = 2*ctgx*(-1/sin^2x)*lnx + ctg^2x/x;
g'(x) = x^(ctg^2x) * (2 * ctgx * (-1/sin^2x) * lnx + (ctg^2x)/x);
f(x) = y = 2x^(ctgx^2)*(5x^3 + x^(1/3));
f'(x) = 2 * g'(x) * (5x^3 + x^(1/3)) + 2 * g(x) * (15x^2 + 1/3x^(-2/3));
f'(x) = 2 * x^(ctg^2x) * (2 * ctgx * (-1/sin^2x) * lnx + (ctg^2x)/x) * (5x^3 + x^(1/3)) + 2 * x^(ctg^2x) * (15x^2 + (1/3)x^(-2/3)).