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ksusha9877
@ksusha9877
July 2022
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[tex] \int\limits^8_1 \, \sqrt[3]{x} dx [/tex]
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DedushkaBake
8
=∫ x^(1/3)dx=
1
8
=((x^(1/3+1))/(1/3+1)) =
1
8
=(3/4) (x^(4/3))=(3/4)[ 8^(4/3)-1^(4/3)]=(3/4)[2^4-1]=3(16-1)/4=45/4=
1
=11,25
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Answers & Comments
=∫ x^(1/3)dx=
1
8
=((x^(1/3+1))/(1/3+1)) =
1
8
=(3/4) (x^(4/3))=(3/4)[ 8^(4/3)-1^(4/3)]=(3/4)[2^4-1]=3(16-1)/4=45/4=
1
=11,25