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NasyaGurta
@NasyaGurta
July 2022
1
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Помогите решить
[tex] \left \{ {x^{2} - y^{2} = 0 } \atop {4+xy=0}} \right. [/tex]
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n1982
Х=-4/у
(-4/у)²-у²=0
16/у²-у²=0
16-у∧4=0
(4-у²)(4+у²)=0
у²=4
у=2
у=-2
у²=-4- корней нет
у=2
х=-2
у=-2
х=2
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Answers & Comments
(-4/у)²-у²=0
16/у²-у²=0
16-у∧4=0
(4-у²)(4+у²)=0
у²=4
у=2
у=-2
у²=-4- корней нет
у=2
х=-2
у=-2
х=2