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PolinaDub
@PolinaDub
August 2021
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Объясните пожалуйста как решать
36√3tg[tex] \frac{ \pi }{3} [/tex]sin[tex] \frac{ \pi }{6} [/tex]
4sin[tex] \frac{ 17\pi }{12} [/tex]*cos[tex] \frac{ 17\pi }{12} [/tex]
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nKrynka
Решение
1) 36√3 * tg(π/3) * sin(π/6) = 36√3 * √3 * (1/2) = 54
2) 4*sin(17π/12) * cos(17π/12) = 2sin[2*(17π/12)] = 2sin(17π/6) =
= 2*sin[(12π + 5π)/6] = 2*sin(2π + 5π/6) = 2*sin(5π/6) = 2*(1/2) = 1
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Answers & Comments
1) 36√3 * tg(π/3) * sin(π/6) = 36√3 * √3 * (1/2) = 54
2) 4*sin(17π/12) * cos(17π/12) = 2sin[2*(17π/12)] = 2sin(17π/6) =
= 2*sin[(12π + 5π)/6] = 2*sin(2π + 5π/6) = 2*sin(5π/6) = 2*(1/2) = 1