пожалуйста,помогите упростить
[tex]4ctg^{2} 2 \alpha +9- \frac{1+cos4 \alpha }{2sin^{2}*cos^{2} \alpha } [/tex]
[tex]4ctg^{2} 2 \alpha +9- \frac{1+cos4 \alpha }{2sin^{2}*cos^{2} \alpha } [/tex]
More Questions From This User See All
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
4ctg²2α+9-(1+cos4α)/(2sin²α * cos²α)==4ctg² 2α+9-(1+cos2*(2α))/ [ (1/2)*(2sinα *cosα)² ]=
=4ctg²2α+9-2*(1+2cos²2α-1)/(sin2α)²=4ctg²2α+9-4cos²2α/sin²2α=
=4ctg²2α+9-4ctg²2α=9