Найти предел ( написать с пояснением): [tex]\lim_{x \to \infty} \frac{14x^{2}+3x+\sqrt{x^{3} } }{7x^{2} +2x+8}[/tex]. Created by banan1v1nutele. algebra-ru

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banan1v1nutele @banan1v1nutele

November 2021 1 9 Report

Найти предел ( написать с пояснением):
[tex]\lim_{x \to \infty} \frac{14x^{2}+3x+\sqrt{x^{3} } }{7x^{2} +2x+8}[/tex]

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NNNLLL54

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Ответ:

$\displaystyle \lim_{n \to \infty}\, \frac{14x^2+3x+\sqrt{x^3}}{7x^2+2x+8}=\lim_{n \to \infty}\, \frac{14+\dfrac{3}{x}+\sqrt{\dfrac{1}{x}}}{7+\dfrac{2}{x}+\dfrac{8}{x^2}}=\frac{14+0+0}{7+0+0}=\frac{14}{7}=2$

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