tex]...

June 2022 1 11 Report

решите систему методом замены переменной
Ребят помогите срочно(((

[tex] \left \{ 2(x+y)^2+3(x+2y)=5 \atop3(x+2y)-2x-2y=5[/tex]

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Матов

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$x+y=a ; x+2y=b \\
2a^2+3b=5 \\ 3b-2a=5 \\\\ 
2a^2+2a=0 \\
a=0 ; a=-1 \\
b= \frac{5}{3} ; b=1 \\\\
1) x+y=0 \\ x+2y=\frac{5}{3} \\
 y=\frac{5}{3} ; x=-\frac{5}{3} \\\\
 2) x+y=-1 \\ x+2y=1 \\\
 y=2 ; x=-3$

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kukushkinao July 2022 | 0 Ответы

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