[tex] \frac{1+cos2x}{1-sinx}=0[/tex]
одз:1)1+cos2x=0
cos2x=-1
2x=pi+2pik .k=z
x=pi/2+pik . k=z
2)1-sinx≠0
sinx≠1
x≠pi/2+2pik . k=z
получаем ответ:
x=-pi/2+2pik . k=z
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одз:
1)1+cos2x=0
cos2x=-1
2x=pi+2pik .k=z
x=pi/2+pik . k=z
2)1-sinx≠0
sinx≠1
x≠pi/2+2pik . k=z
получаем ответ:
x=-pi/2+2pik . k=z