1)[tex] \sqrt{2x+1} = \sqrt{ x^{2} -2x+4}[/tex]
2)[tex] \sqrt{x} = \sqrt{ x^{2} -x-3} [/tex]
3)[tex] \sqrt{x+2} = \sqrt{2x-3} [/tex]
4)[tex] \sqrt{9- x^{2} } = \sqrt{x+9} [/tex]
2)[tex] \sqrt{x} = \sqrt{ x^{2} -x-3} [/tex]
3)[tex] \sqrt{x+2} = \sqrt{2x-3} [/tex]
4)[tex] \sqrt{9- x^{2} } = \sqrt{x+9} [/tex]
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1) ОДЗ: х ≥ -0,52x + 1 = x² - 2x + 4
x² - 4x + 3 = 0
(x - 3)(x - 1) = 0
x₁ = 1; x₂ = 3
2) х ≥ 0
x = x² - x - 3
x² - 2x - 3 = 0
(x - 3)(x+1) = 0
x₁ = -1 - не подходит
x₂ = 3
Ответ: 3
3) x ≥ - 2
x + 2 = 2x - 3
x = 5
4) ОДЗ: [-3; 3]
9 - x² = x + 9
x² + x = 0
x₁ = 0
x₂ = -1