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KyziaBanan
@KyziaBanan
July 2022
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Решите уравнение [tex]log_{2}^{2} x+log_{2} \frac{2}{x} = 3[/tex]
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Verified answer
Log²₂(x) + log₂(2) - log₂(x) - 3 = 0
log²₂(x) + 1 - log₂(x) - 3 = 0
log²₂(x) - log₂(x) - 2 = 0
log₂(x) = t
t² - t - 2 = 0
D = 1 + 8 = 9
t = 2 или t = - 1
log₂(x) = 2 log₂(x) = - 1
x = 4 x = 1/2
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Answers & Comments
Verified answer
Log²₂(x) + log₂(2) - log₂(x) - 3 = 0log²₂(x) + 1 - log₂(x) - 3 = 0
log²₂(x) - log₂(x) - 2 = 0
log₂(x) = t
t² - t - 2 = 0
D = 1 + 8 = 9
t = 2 или t = - 1
log₂(x) = 2 log₂(x) = - 1
x = 4 x = 1/2