Помогите решить [tex] \frac{9x+5}{3x+10}- \frac{3x+7}{x+6}=0 [/tex]. Created by CKyTepucT. matematika-ru

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Помогите решить
[tex] \frac{9x+5}{3x+10}- \frac{3x+7}{x+6}=0 [/tex]

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ОДЗ:
3x + 10 ≠ 0
x + 6 ≠ 0

x ≠ -10/3
x ≠ -6

Умножим всё уравнение на (3x + 10)(x + 6)
(9x + 5)(x + 6) - (3x + 7)(3x + 10) = 0
(9x² + 54x + 5x + 30) - (9x² + 30x + 21x + 70) = 0
(9x² + 59x + 30) - (9x² + 51x + 70) = 0
9x² - 9x² + 59x - 51x + 30 - 70 = 0
8x = 40
x = 5
Ответ: x = 5.

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sedinalana (9x+5)(x+6)-(3x+7)(3x+10)=0;x≠-10/3;x≠-6
9x²+54x+5x+30-9x²-30x-21x-70=0
8x=40
x=40:8
x=5

0 votes Thanks 0

Answers & Comments

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