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nickie
@nickie
August 2022
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выполнить действия [tex] \frac{b-c}{a+b}- \frac{ab-b^2}{a^2-ac}* \frac{a^2-c^2}{a^2-b^2} [/tex]
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iriska124
1) b*(a-b)\a*(a-c)*((a-c)*(a+c)\(a-b)*(a+b) =b*(a+c)\a*(a+b)
2)b-c\a+b - b*(a+c)\a*(a+b) = a*(b-c)-b*(a-c)\a*(a+b) =ab-ac-ab+bc\a*(a+b)=bc-ac\a*(a+b) =c*(b-a)\a*(a+b)=-c*(a+b)\a*(a+b)=-c\a
Ответ ---------- (-с\а)
1 votes
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Радость25
Решение смотри во вложении:
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Answers & Comments
2)b-c\a+b - b*(a+c)\a*(a+b) = a*(b-c)-b*(a-c)\a*(a+b) =ab-ac-ab+bc\a*(a+b)=bc-ac\a*(a+b) =c*(b-a)\a*(a+b)=-c*(a+b)\a*(a+b)=-c\a
Ответ ---------- (-с\а)