вывести из под корня [tex]3b \sqrt{5b} = [/tex][tex] \sqrt{48 {y}^{8} } = [/tex]8кл!!. Created by aselkazbekova999. algebra-ru

tex]8кл!!...

aselkazbekova999 @aselkazbekova999

July 2022 1 11 Report

вывести из под корня
[tex]3b \sqrt{5b} = [/tex]
[tex] \sqrt{48 {y}^{8} } = [/tex]
8кл!!

Answers & Comments

NNNLLL54

Verified answer

Ответ:

$1)\ \ 3b\sqrt{5b}=\sqrt{(3b)^2\cdot 5b}=\sqrt{9b^2\cdot 5b}=\sqrt{45b^3}\\\\\\2)\ \ \sqrt{48y^8}=\sqrt{16\cdot 3(y^4)^2}=4\cdot |y^4|\cdot \sqrt{3}=4\cdot y^4\, \sqrt3$

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Verified answer

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