Приведите дробь [tex] \frac{a}{x-2} [/tex] к знаменателю:
a) 2-x; d) 4-4x+[tex] x^{2} [/tex]
b) 0,5x-1; e) [tex] x^{3} [/tex]-8
c) 4-[tex] x^{2} [/tex]
a) 2-x; d) 4-4x+[tex] x^{2} [/tex]
b) 0,5x-1; e) [tex] x^{3} [/tex]-8
c) 4-[tex] x^{2} [/tex]
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Verified answer
A/(x-2)=-a/(2-x)a/(x-2)=a(x-2)/(x-2)²
a/(x-2)=0,5a/(0,5x-1)
a/(x-2)=a(x²+2x+4)/(x³-8)
a/(x-2)=-a(x+2)/(4-x²)