Решите уравнение [tex] \frac{ {x}^{2} + 2x + 4}{ {x}^{3} - 8} = \frac{5}{7} [/tex]. Created by vichodya1. algebra-ru

Ответ:Объяснение:

tex]...

vichodya1 @vichodya1

July 2022 1 5 Report

Решите уравнение
[tex] \frac{ {x}^{2} + 2x + 4}{ {x}^{3} - 8} = \frac{5}{7} [/tex]

Answers & Comments

GoldmanYT

Ответ:

$x =\frac {17}{5}$

Объяснение:

$\frac {x^2+2x+4}{x^3-8}=\frac {5}{7} \\ \frac {x^2+2x+4}{(x-2)(x^2+2x+4)}=\frac {5}{7} \\ x\neq2 \\ 7 (x^2+2x+4)=5 (x-2)(x^2+2x+4) \\ 5x - 17=0 \\ x =\frac {17}{5}$

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najdite koren uravneniya157a9bc66dff5da86a5058cba0a5bb94 54121

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pomogite reshit 3x46x 2

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