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November 2021 1 27 Report

Упростить выражение:
[tex]\frac{ \sqrt{3}cos2 \alpha + sin2 \alpha}{cos \alpha +\sqrt{3}sin\alpha}[/tex]

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Montale $\frac{ \sqrt{3}cos 2a+sin2a }{cosa+ \sqrt{3}sina }$ = $\frac{-(2 \sqrt{3} sin^2a-2cosa sina- \sqrt{3} }{ \sqrt{3}sina+cosa}$ = $\frac{2cosa sina+2 \sqrt{3}cos^2a- \sqrt{3} }{ \sqrt{3} sina+cosa}$ = $\sqrt{3} cosa-sina$

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