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Dasha91198
@Dasha91198
August 2022
1
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помогите решить показательное уравнение
[tex]3^x *7^x^+^2=49*4^x [/tex]
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nKrynka
(3^x)*(7^x)*(7^2) = (7^2)*((4^x) / делим на (7^2)*((4^x)
(21/4)^x = 1
(21/4)^x = (21/4)^:0
х = 0
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Answers & Comments
(21/4)^x = 1
(21/4)^x = (21/4)^:0
х = 0