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IraqIsraelovich
@IraqIsraelovich
July 2022
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Составьте квадратное уравнение с целыми коэффициентами, корни которого равны:
1) -7 и -8
2) 5 и -0,4
3) [tex] \frac{1}{2} [/tex] и [tex] \frac{2}{3} [/tex]|
4) 5 - [tex]\sqrt{10} [/tex] и 5 + [tex]\sqrt{10} [/tex]
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erik2004777
По теореме Виета х1+х2=-p
x1*x2=q
1)-7+(-8)=-15
-7*(-8)=56
x^2+15x+56=0
2)x^2-4.6x-2=0
3)x^2+1.5/30x+1/3=0
4)x^2-250=0
5 votes
Thanks 4
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Answers & Comments
x1*x2=q
1)-7+(-8)=-15
-7*(-8)=56
x^2+15x+56=0
2)x^2-4.6x-2=0
3)x^2+1.5/30x+1/3=0
4)x^2-250=0