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Vampire100
@Vampire100
August 2022
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1. Найдите производную функции:
а). [tex]y= x^{2} lnx[/tex]
б). [tex]y= 3lnx+sin2x[/tex]
2. Найдите значение производной заданной функции в указанной точке:
а). [tex]y= lnx+x, x_{0}= \frac{1}{7} [/tex]
б). [tex]y= x^{3}lnx , x_{0}= e [/tex]
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Answers & Comments
vadim899
1) y'=2xln(x)+x
2) y'=3/x+2cos2x
3)y'=1/x+1
y'(x0)=8
4)y'=3x^2ln(x)+x^2
y'(x0)=4e^2
2 votes
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Answers & Comments
2) y'=3/x+2cos2x
3)y'=1/x+1
y'(x0)=8
4)y'=3x^2ln(x)+x^2
y'(x0)=4e^2