tex]...

June 2022 1 27 Report

Сократите дробь :
а) x-18/[tex] \sqrt{x} [/tex] + [tex]3\sqrt{2} [/tex]

б) 4[tex] a^{2} [/tex] - [tex] 4a \sqrt{3b} [/tex] + 3b / [tex] 2a\sqrt{b} [/tex] - [tex] b\sqrt{3} [/tex]

Answers & Comments

NNNLLL54

Verified answer

$1)\; \; \; \frac{x-18}{\sqrt{x}+3\sqrt2} = \frac{(\sqrt{x})^2-(\sqrt{18})^2}{\sqrt{x}+\sqrt{9\cdot 2}} = \frac{(\sqrt{x}-\sqrt{18})(\sqrt{x}+\sqrt{18})}{\sqrt{x}+\sqrt{18}} =\\\\=\sqrt{x}-\sqrt{18}=\sqrt{x}-3\sqrt2\\\\2)\; \; \; \frac{4a^2-4a\sqrt{3b}+3b}{2a\sqrt{b}-b\sqrt3} = \frac{(2a)^2-2\cdot (2a)\cdot \sqrt{3b}+(\sqrt{3b})^2}{\sqrt{b}\cdot (2a-\sqrt{b}\cdot \sqrt3)} =\\\\=\frac{(2a-\sqrt{3b})^2}{\sqrt{b}\cdot (2a-\sqrt{3b})} =\frac{2a-\sqrt{3b}}{\sqrt{b}}$

1 votes Thanks 1

Answers & Comments

Verified answer

osobennosti stroeniya skeleta mlekopitayushih 1 skelet golovy 2 skelet tulovisha

kg gradusy najti t1 si300 g 03 kgreshenieq1

napisat uravneniya po cepochke prevrasheniya a p p2o5 h3po4 mg3po43 b ca

srochno 50 b opredelite silu tyagoteniya mezhdu zemlej i lunoj esli rasstoyanie

dlya kakogo vida smesej primenim sposob razdeleniya filtrovanie dlya kakih hromat

povest v durnom obshestve ili eti podzemelya kakoj pokazala sebya devochka so

1 belaya planariya otlichaetsya ot kishechnopolostnyh zhivotnyh a radialnoj simmetri

1 ameba obyknovennaya predstavlyaet soboj kak kletochnyj uroven organi

sostavte vozmozhnye uravneniya himicheskoj reakcii 1 li o2 2 mg o2 3 al

tex] - 5a...

рекомендуемые вопросы

Helpful Links

Helpful Social