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ksella2002
@ksella2002
July 2022
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[tex]m^3-n^3+2n-2m[/tex]
[tex]3a^3-3b^3+5a^2-5b^2[/tex]
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Verified answer
1)=(m-n)(m^2+mn+n^2)-2(m-n)=(m-n)(m^2+mn+n^2-2)
2)=3(a^3-b^3)-5(a^2-b^2)=3(a-b)(a^2+ab+b^2)-5(a-b)(a+b)=(a-b)(3a^2+3ab+3b^2-5a-5b)
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Answers & Comments
Verified answer
1)=(m-n)(m^2+mn+n^2)-2(m-n)=(m-n)(m^2+mn+n^2-2)2)=3(a^3-b^3)-5(a^2-b^2)=3(a-b)(a^2+ab+b^2)-5(a-b)(a+b)=(a-b)(3a^2+3ab+3b^2-5a-5b)