Решить:[tex] \frac{a {}^{3} b \: - \: ab {}^{3} }{ {a}^{2} + \: ab \: - \: 3a \: - \: 3b} [/tex]. Created by mihanbay29. algebra-ru

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mihanbay29 @mihanbay29

July 2022 1 12 Report

Решить:
[tex] \frac{a {}^{3} b \: - \: ab {}^{3} }{ {a}^{2} + \: ab \: - \: 3a \: - \: 3b} [/tex]

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sangers1959

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Объяснение:

$\frac{a^3b-ab^3}{a^2+ab-3a-3b}=\frac{ab*(a^2-b^2)}{(a^2-3a)+(ab-3b)}=\frac{ab*(a+b)*(a-b)}{a*(a-3)+b*(a-3)}=\frac{ab*(a+b)*(a-b)}{(a-3)*(a+b)}=\frac{ab*(a-b)}{a-3}.$

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privet ot tebya trebuetsya vsego otvet nuzhno najti srednyuyu skorost zaranee spa

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