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[tex] \frac{sin 3L}{sin L}- \frac{cos 3L}{cos L}=2 [/tex]
[tex] \frac{sin 3L}{sin L}- \frac{cos 3L}{cos L}=2 [/tex]
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(sin3αcosα-cos3αsinα)/sinαcosα=sin(3α-α)/sinαcosα=sin 2α/sinαcosα=2sinαcosα/sinαcosα=2