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Holy69
@Holy69
July 2022
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[tex]1)7 ^{3-2x} =49
2)(\frac{1}{2}) ^{2x-3}=3[/tex]
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Answers & Comments
manyny06
1.
7 в степени (3-2х) = 7 ²
основания одинаковые, их можно опустить
3-2х=2
-2х= 2-3
-2х = -1
х=1\2
2.
2х-3 =log₀₅ 3
2x = log₀₅ 3 + 3
x= 1\2 (log₀₅ 3 + 3)
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Answers & Comments
7 в степени (3-2х) = 7 ²
основания одинаковые, их можно опустить
3-2х=2
-2х= 2-3
-2х = -1
х=1\2
2.
2х-3 =log₀₅ 3
2x = log₀₅ 3 + 3
x= 1\2 (log₀₅ 3 + 3)