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a) b[tex] \frac{1}{2} [/tex]·b-[tex]\frac{1}{4} [/tex]
б) y[tex] \frac{2}{3}[/tex]·y-1/y[tex] \frac{1}{3}[/tex]
a) b[tex] \frac{1}{2} [/tex]·b-[tex]\frac{1}{4} [/tex]
б) y[tex] \frac{2}{3}[/tex]·y-1/y[tex] \frac{1}{3}[/tex]
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b) y^ 2/3+1 - 1/y^1/3 = y^5/3 - 1/y^1/3 = y^2-1 / y^1/3