решите этот [tex](x+5)^2=(x-1)^2-48[/tex]и [tex](x-2)^2-(x-3)^2=-54[/tex]. Created by frozenolaf1. algebra-ru

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frozenolaf1 @frozenolaf1

July 2022 1 6 Report

решите этот [tex](x+5)^2=(x-1)^2-48[/tex]
и
[tex](x-2)^2-(x-3)^2=-54[/tex]

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NNNLLL54

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$1.\; (x+5)^2=(x-1)^2-48\\(x+5)^2-(x-1)^2=-48\\(x+5-x+1)(x+5+x-1)+48=0\\6(2x+4)+48=0|:6\\2x+4+8=0\\2x=-12\\x=-6\\\\2.\; (x-2)^2-(x-3)^2=-54\\(x-2-x+3)(x-2+x-3)=-54\\1\cdot 2x-5=-54\\2x=-49\\x=-24,5$

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