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SDD15
@SDD15
July 2022
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помогите пожалуйста решить уравнение
[tex] 13^{2x+1} -13^{x} -12=0[/tex]
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pomoshnik09
13*13^2x-13^x-12=0 пусть 13^x=t, t>0
13t²-t-12=0 D=(-1)²-4*13*-12=1+624=625
t1=1+√625)/(2*13)=(1+25)/26=1
t2=(1-25)/(2*13)=-24/26=-12/13
-12/13-посторонний корень
получили 13^x=1 13^x=13^0 x=0
ответ 0
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Answers & Comments
13t²-t-12=0 D=(-1)²-4*13*-12=1+624=625
t1=1+√625)/(2*13)=(1+25)/26=1
t2=(1-25)/(2*13)=-24/26=-12/13
-12/13-посторонний корень
получили 13^x=1 13^x=13^0 x=0
ответ 0