Найдите промежутки возрастания и убывания функции [tex]y=-3x+ e^{3x} [/tex]. Created by dyundikmaxim2. algebra-ru

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July 2022 1 13 Report

Найдите промежутки возрастания и убывания функции [tex]y=-3x+ e^{3x} [/tex]

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$y=-3x+e^{3x}\\\\y'=-3+3e^{3x}=3(e^{3x}-1)=0\\\\e^{3x}=1\; \; \to \; \; 3x=0\; ,\; \; x=0\\\\-----(0)+++++\\\\vozrastaet\; na\; \; (0,+\infty )\\\\ybuvaet\; na\; \; (-\infty ,0)$

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