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1)[tex] \int\limits{\frac{cos2x }{sin^2x*cos^2x}} \, dx [/tex]
2)[tex] \int\limits { \frac{cos^2x+2cosx-3}{3cosx} } \, dx [/tex]
1)[tex] \int\limits{\frac{cos2x }{sin^2x*cos^2x}} \, dx [/tex]
2)[tex] \int\limits { \frac{cos^2x+2cosx-3}{3cosx} } \, dx [/tex]
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2) =1/3integral (cosx+2/3-3/cosx)dx=1/3(int cosxdx+2-3int1/cosx dx)=1/3(sinx+2x+int(sin^2x+cos^2x)/cosx ???