Упростите [tex] (\frac{3a}{a+3} + 3a) x \frac{a+3}{3a ^{2} } [/tex]. Created by kp99. algebra-ru

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Упростите [tex] (\frac{3a}{a+3} + 3a) x \frac{a+3}{3a ^{2} } [/tex]

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nafanya2014

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$(\frac{3a}{a+3} + 3a) \cdot \frac{a+3}{3a ^{2} }= \frac{3a+3a(a+3)}{a+3} \cdot\frac{a+3}{3a ^{2} }= \frac{3a(1+a+3)}{a+3} \cdot\frac{a+3}{3a ^{2} }= \frac{a+4}{a} 
$

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