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Aru999
@Aru999
July 2022
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[tex]1) \frac{x^2-3x}{x^2+7x-30} = \frac{5x^2-x-42}{x^2+7x-30}
2) x^2+ \frac{3x-1}{x+4}=16- \frac{1-3x}{x+4}
3) \frac{1}{3x+2}+ \frac{3}{5x+6}= \frac{2}{7x+8}[/tex]
4)[tex] \frac{12}{x^2-9} + \frac{x}{x+3}= \frac{2}{x-3} [/tex]
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ВладимирБ
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