Помогите решить:[tex] \frac{x}{xy-y^2} : \frac{x}{x^2-y^2} [/tex]. Created by DnoKaKtys. algebra-ru

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[tex] \frac{x}{xy-y^2} : \frac{x}{x^2-y^2} [/tex]

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nafanya2014

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$\frac{x}{xy-y^2} : \frac{x}{x^2-y^2} =\frac{x}{xy-y^2} \cdot \frac{x^2-y^2}{x} =\frac{x}{y(x-y)} \cdot \frac{(x-y)(x+y)}{x} = \frac{x+y}{y} 

$

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2 perioda

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6x6koren iz 3mozhno tak umnozhat

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Verified answer

tex]...

x-3=4...

vstavte vmesto propuskov po konstitucii avtorom kotoroj byl dekabrist

kto yavlyaetsya yavlyaetsya lishnim v ryadu g kurin n raevskij e chetvertakov

2 perioda

b)...

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6x6koren iz 3mozhno tak umnozhat

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