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Фиолета
@Фиолета
September 2021
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Помогите, пожалуйста! (И объясните мне, пожалуйста!)
1) [tex] \sqrt{12*27}[/tex]
2) [tex] \sqrt{5*45} [/tex]
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1)√(12*27)=√(3*4*3*9)=√(3^2*2^2*3^2)=3*2*3=18
2)√(5*45)=√(5*5*9)=√(5^2*3^2)=5*3=15
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Verified answer
1)√(12*27)=√(3*4*3*9)=√(3^2*2^2*3^2)=3*2*3=182)√(5*45)=√(5*5*9)=√(5^2*3^2)=5*3=15