Плиззз вообще непонятно [tex] \frac{4¹⁰· (2⁴)³}{4² · (2²)¹²} [/tex]. Created by milashcalennova. algebra-ru

tex]...

August 2021 1 1 Report

Плиззз вообще непонятно
[tex] \frac{4¹⁰· (2⁴)³}{4² · (2²)¹²} [/tex]

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signora $\frac{4^1^0*(2^4)^3}{4^2*(2^2)^1^2}= \frac{(2^2)^1^0*(2^4)^3}{(2^2)^2*(2^20^12} =$ $= \frac{2^2^0*2^1^2}{2^4*2^2^4} = \frac{2^3^2}{2^2^8} =2^4=16$
задание правильно ?

2 votes Thanks 1

milashcalennova да правильно

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milashcalennova July 2022 | 0 Ответы

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