Чему равен корень уравнения:
1) [tex] \frac{x-8}{x+2} [/tex]=[tex]\frac{7}{3} [/tex]
2) [tex] \frac{4}{x-1,2} [/tex]=[tex] \frac{15}{x-10} [/tex]
1) [tex] \frac{x-8}{x+2} [/tex]=[tex]\frac{7}{3} [/tex]
2) [tex] \frac{4}{x-1,2} [/tex]=[tex] \frac{15}{x-10} [/tex]
Answers & Comments
3(х-8) = 7(х+2)
3х-24 = 7х+14
7х-3х = -24-14
4х = -38
х = -38/4
х = -19/2
х = -9,5
2) 4/(х-1,2) = 15/(х-10)
4(х-10) = 15(х-1,2)
4х-40 = 15х-18
15х-4х = -40+18
11х = -22
х = -22/11
х = -2