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Benthas
@Benthas
July 2022
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СРОЧНО ПОМОГИТЕ!!!!
Решите уравнение методом интервалов:
[tex] \frac{(x - 1) {(7x + 3)}^{2} }{x} \leqslant 0[/tex]
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армения20171
(x-1)(7x+3)²/x≤0
x-1=0;x=1
(7x+3)²>0
x≠0
__+___0__-____1_____+___
x€(0;1]
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Benthas
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x-1=0;x=1
(7x+3)²>0
x≠0
__+___0__-____1_____+___
x€(0;1]