[tex](\frac{10}{\sqrt{11} - \sqrt{6} } - \frac{4}{ \sqrt{11}-3 } + \frac{19}{ \sqrt{6} +5 } ) *( \sqrt{6} +1)[/tex]. Created by Pheia. matematika-ru

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[tex](\frac{10}{\sqrt{11} - \sqrt{6} } - \frac{4}{ \sqrt{11}-3 } + \frac{19}{ \sqrt{6} +5 } ) *( \sqrt{6} +1)[/tex]

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mukus13

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$(\frac{10}{ \sqrt{11} - \sqrt{6} } - \frac{4}{ \sqrt{11} -3} + \frac{19}{ \sqrt{6}+5 } )*( \sqrt{6}+1)=$ $(\frac{10*( \sqrt{11}+ \sqrt{6} )}{ (\sqrt{11} - \sqrt{6} )( \sqrt{11} + \sqrt{6}) } - \frac{4*( \sqrt{11}+3) }{ (\sqrt{11} -3)( \sqrt{11} +3)} + \frac{19*( \sqrt{6} -5)}{ (\sqrt{6}+5)( \sqrt{6} -5) } )*( \sqrt{6}+1)=$ $(\frac{10*( \sqrt{11}+ \sqrt{6} )}{ 11-6 } - \frac{4*( \sqrt{11}+3) }{ 11-9} + \frac{19*( \sqrt{6} -5)}{ 6-25 } )*( \sqrt{6}+1)=$ $(\frac{10*( \sqrt{11}+ \sqrt{6} )}{ 5 } - \frac{4*( \sqrt{11}+3) }{ 2} + \frac{19*( \sqrt{6} -5)}{ -19} )*( \sqrt{6}+1)=$ $(2*( \sqrt{11} + \sqrt{6} )-2*( \sqrt{11}+3)-( \sqrt{6} -5))( \sqrt{6} +1)=(2 \sqrt{11} +2 \sqrt{6}$ $-2 \sqrt{11}-6- \sqrt{6}+5)( \sqrt{6} +1)=( \sqrt{6} -1)( \sqrt{6} +1)=( \sqrt{6} )^2-1=$ $=6-1=5$

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koren iz 11 47 minus koren iz 32107

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