решите неравенство (1 9/16)^log_7(x+1)>(4/5)^log_1/7(x+3)
если быть точнее
[tex](1 \times \frac{9}{16} ) {}^{ log_{7}(x + 1) } > ( \frac{4}{5} ) {}^{ log_{ \frac{1}{7} }(x + 3) } [/tex]
и второе
[tex] log_{x - 2}(2) + log_{x - 2}(x {}^{2} ) \leqslant log_{x - 2}(13x - 20) [/tex]
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