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lubkaktys2012
@lubkaktys2012
August 2022
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Решите уравнение
2[tex]2 x^{2} +3x-3= x^{2} -3x+(-2+ x^{2} )[/tex]
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Света19999
Verified answer
2x^2 + 3x - 3 = x^2 - 3x + (-2+x^2)
2x^2 + 3x - 3 - x^2 + 3x -(-2+x^2) = 0
x^2 +6x - 3 + 4 - x^2 =0
6x = -1
x = -1/6
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Answers & Comments
Verified answer
2x^2 + 3x - 3 = x^2 - 3x + (-2+x^2)2x^2 + 3x - 3 - x^2 + 3x -(-2+x^2) = 0
x^2 +6x - 3 + 4 - x^2 =0
6x = -1
x = -1/6