[tex]log_6{234}- log_6{6,5} +log_16 log_3{9}[/tex]. Created by zalka62. matematika-ru

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July 2022 2 7 Report

[tex]log_6{234}- log_6{6,5} +log_16 log_3{9}[/tex]

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$log_{6}(234) - log_{6}(6.5) + log_{16}( log_{3}(9) ) = \\ = log_{6}( \frac{234}{6.5} ) + log_{16}(2) = log_{6}(36) + log_{16}(2) = \\ = 2 + \frac{1}{4} = 2 + 0.25 = 2.25 \\$

ОТВЕТ: 2,25

2 votes Thanks 2

tomom

log6(234/6,5)+log2^4 (log3(3^2))=log6(36)+log2^4(2)=log6 (6^2)+1/4=2+1/4=9/4=2 1/4=2,25

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Answers & Comments

Verified answer

y2x88 najti proizvodnuyu

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8 pomogite reshit8c9c58ddab4f1f01903841ad0e202a0f 78018

log10 250 log10 2 5 log16 log6 36

2^2-x=16 4^1-2x=64 2^1-x=8...

4x 72 pomogite pozhalujsta

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23 x32 pomogite reshit

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