помогите очень срочно нужно [tex]sin( \pi cos3x)=1[/tex]. Created by abieva. matematika-ru

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August 2022 1 48 Report

помогите очень срочно нужно
[tex]sin( \pi cos3x)=1[/tex]

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irka1804 Sin(πcos3x) = 1
πcos3x = π/2 + 2πn, n ∈ Z
cos3x = 1/2 + 2n, n ∈ Z
-1 ≤ cos3x ≤ 1
-1 ≤ 1/2 + 2n ≤ 1
-3/2 ≤ 2n ≤ 1/2
n = 0
cos3x = 1/2
3x = +- π/3 + 2πk, k ∈ Z

x = +- π/9 + 2πk / 3, k ∈ Z

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abieva ой, я уже решила ;) спасибо

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kak nazyvayutsya zhivotnye vseyadnye rastitelnoyadnye i hishnye

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